Must Have
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How much work must be done to the gas compression factors. 8.00, starting from the first volume?
551 J of the need to compress gas to the first half. Volume constant temperature. How much work must be done to the gas compression factors. 8.00, starting from the first volume?
Process isothermal> PV = RT = K (say). const temp job doing DW = k PdV = (DV / V) and from V1 to V2 W k = (e). (V2/V1) -------------- -------------------- 551 log k = (e) [(V1 /. 2) / V1] log k = (e) [(1 / 2)] 551 = log k - (e) (2) -------- (1) is the compression factor. 2 or V2/V1 = 1 / 2 ------------------------- For compression factors. 8 or V2/V1 = 1 / 8 W = log k - (e) (8) -------- (2) =============== (2) /. (1) log W = 551 * (e) (8). / Log (e) (2) log W = 551 * (e) (2 ^ 3) / log (e) (2) W = 551 * 3 log (e) (2 *) / log (e) (2). W = 1,653 Joule to work. Compression by factors from 8 to enter the size.


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